Trumbauersville is a borough in Bucks County, Pennsylvania, United States. The population was 974 at the 2010 census.
Trumbauersville is located at 40°24′41″N 75°22′54″W (40.411305, -75.381577).
According to the United States Census Bureau, the borough has a total area of 0.4 square miles (1.0 km2), all of it land.
As of the 2010 census, the borough was 95.4% White, 0.6% Black or African American, 0.3% Native American, 0.8% Asian, 0.1% Native Hawaiian or Other Pacific Islander, and 0.6% were two or more races. 3.1% of the population were of Hispanic or Latino ancestry.
As of the census of 2000, there were 1,059 people, 374 households, and 305 families residing in the borough. The population density was 2,475.2 people per square mile (950.9/km²). There were 382 housing units at an average density of 892.8 per square mile (343.0/km²). The racial makeup of the borough was 97.92% White, 0.57% African American, 0.66% Asian, 0.47% from other races, and 0.38% from two or more races. Hispanic or Latino of any race were 0.85% of the population.
There were 666 households, out of which 39.8% had children under the age of 18 living with them, 69.0% were married couples living together, 7.8% had a female householder with no husband present, and 18.4% were non-families.