Mowrystown is a village in Highland County, Ohio, United States. The population was 360 at the 2010 census.
Mowrystown was laid out in 1829, and named after Abe Mowry, an early settler.
Mowrystown is located at 39°2′20″N 83°45′9″W (39.038827, -83.752457). According to the United States Census Bureau, the village has a total area of 0.49 square miles (1.27 km2), of which 0.48 square miles (1.24 km2) is land and 0.01 square miles (0.03 km2) is water.
As of the census of 2010, there were 360 people, 129 households, and 92 families living in the village. The population density was 750.0 inhabitants per square mile (289.6/km2). There were 152 housing units at an average density of 316.7 per square mile (122.3/km2). The racial makeup of the village was 99.7% White and 0.3% from two or more races.
There were 129 households, of which 38.0% had children under the age of 18 living with them, 46.5% were married couples living together, 17.8% had a female householder with no husband present, 7.0% had a male householder with no wife present, and 28.7% were non-families. 23.3% of all households were made up of individuals, and 12.4% had someone living alone who was 65 years of age or older. The average household size was 2.79 and the average family size was 3.27.