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Eden is a census-designated place (CDP) in Sweetwater County, Wyoming, United States. The population was 281 at the 2010 census.
Eden is located at 42°3′49″N 109°26′27″W (42.063713, -109.440926).
According to the United States Census Bureau, the CDP has a total area of 13.5 square miles (35.0 km2), of which all of it was land.
As of the census of 2000, there were 388 people, 142 households, and 110 families residing in the CDP. The population density was 5.8 people per square mile (2.2/km2). There were 193 housing units at an average density of 2.9/sq mi (1.1/km2). The racial makeup of the CDP was 97.16% White, 1.55% Native American, 0.26% from other races, and 1.03% from two or more races. Hispanic or Latino of any race were 2.84% of the population.
There were 142 households, out of which 35.9% had children under the age of 18 living with them, 69.0% were married couples living together, 6.3% had a female householder with no husband present, and 22.5% were non-families. 18.3% of all households were made up of individuals, and 4.2% had someone living alone who was 65 years of age or older. The average household size was 2.73 and the average family size was 3.06.
In the CDP, the population was spread out, with 27.8% under the age of 18, 8.5% from 18 to 24, 31.4% from 25 to 44, 26.5% from 45 to 64, and 5.7% who were 65 years of age or older.
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