Greybull is a town in central Big Horn County, Wyoming, United States. The population was 1,847 at the 2010 census.
Greybull is located at 44°29′29″N 108°3′13″W (44.491450, -108.053655).
According to the United States Census Bureau, the town has a total area of 1.83 square miles (4.74 km2), of which 1.82 square miles (4.71 km2) is land and 0.01 square miles (0.03 km2) is water.
As of the census of 2010, there were 1,847 people, 778 households, and 488 families living in the town. The population density was 1,014.8 inhabitants per square mile (391.8/km2). There were 879 housing units at an average density of 483.0 per square mile (186.5/km2). The racial makeup of the town was 92.9% White, 0.4% African American, 1.1% Native American, 0.2% Asian, 0.1% Pacific Islander, 4.5% from other races, and 0.9% from two or more races. Hispanic or Latino of any race were 10.7% of the population.
There were 778 households, of which 31.5% had children under the age of 18 living with them, 50.5% were married couples living together, 7.5% had a female householder with no husband present, 4.8% had a male householder with no wife present, and 37.3% were non-families. 31.9% of all households were made up of individuals, and 12.6% had someone living alone who was 65 years of age or older. The average household size was 2.37 and the average family size was 3.02.