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Ravenswood is a city in Jackson County, West Virginia, United States, along the Ohio River. The population was 3,876 at the 2010 census.
Ravenswood is located at 38°57′11″N 81°45′41″W (38.952922, -81.761357), along the Ohio River at the mouth of Sandy Creek.
According to the United States Census Bureau, the city has a total area of 1.90 square miles (4.92 km2), of which, 1.83 square miles (4.74 km2) is land and 0.07 square miles (0.18 km2) is water.
As of the census of 2010, there were 3,876 people, 1,657 households, and 1,061 families living in the city. The population density was 2,118.0 inhabitants per square mile (817.8/km2). There were 1,807 housing units at an average density of 987.4 per square mile (381.2/km2). The racial makeup of the city was 97.4% White, 0.2% African American, 0.1% Native American, 0.7% Asian, 0.2% from other races, and 1.3% from two or more races. Hispanic or Latino of any race were 1.0% of the population.
There were 1,657 households of which 29.3% had children under the age of 18 living with them, 45.7% were married couples living together, 14.3% had a female householder with no husband present, 4.0% had a male householder with no wife present, and 36.0% were non-families. 32.0% of all households were made up of individuals and 17.8% had someone living alone who was 65 years of age or older. The average household size was 2.30 and the average family size was 2.90.