Rose Hill is a city in Mahaska County, Iowa, United States. The population was 168 at the 2010 census.
Rose Hill is located at 41°19′17″N 92°27′47″W (41.321389, -92.462952).
According to the United States Census Bureau, the city has a total area of 0.14 square miles (0.36 km2), all of it land.
As of the census of 2010, there were 168 people, 72 households, and 47 families living in the city. The population density was 1,200.0 inhabitants per square mile (463.3/km2). There were 85 housing units at an average density of 607.1 per square mile (234.4/km2). The racial makeup of the city was 98.2% White, 0.6% Asian, and 1.2% from two or more races.
There were 72 households, of which 27.8% had children under the age of 18 living with them, 51.4% were married couples living together, 9.7% had a female householder with no husband present, 4.2% had a male householder with no wife present, and 34.7% were non-families. 23.6% of all households were made up of individuals, and 1.4% had someone living alone who was 65 years of age or older. The average household size was 2.33 and the average family size was 2.70.
The median age in the city was 42.4 years.