Sheffield Lake is a city in Lorain County, Ohio, United States. The population was 9,137 at the 2010 census.
Sheffield Lake is located at 41°29′20″N 82°5′59″W (41.488939, -82.099694).
According to the United States Census Bureau, the city has a total area of 2.48 square miles (6.42 km2), all land.
Sheffield Lake was incorporated in 1920. The southern part split off as Sheffield Village in the 1930s.
As of the census of 2010, there were 9,137 people, 3,721 households, and 2,481 families living in the city. The population density was 3,684.3 inhabitants per square mile (1,422.5/km2). There were 4,093 housing units at an average density of 1,650.4 per square mile (637.2/km2). The racial makeup of the city was 94.5% White, 1.7% African American, 0.3% Native American, 0.5% Asian, 0.9% from other races, and 2.2% from two or more races. Hispanic or Latino of any race were 4.9% of the population.
There were 3,721 households, of which 30.3% had children under the age of 18 living with them, 49.7% were married couples living together, 11.4% had a female householder with no husband present, 5.6% had a male householder with no wife present, and 33.3% were non-families. 27.0% of all households were made up of individuals, and 7.6% had someone living alone who was 65 years of age or older.