Sycamore is a village in Wyandot County, Ohio, United States. The population was 861 at the 2010 census.
Sycamore was laid out in 1842, its name derived from nearby Sycamore Creek.
Sycamore is located at 40°57′1″N 83°10′15″W (40.950402, -83.170919).
According to the United States Census Bureau, the village has a total area of 0.64 square miles (1.66 km2), all land.
As of the census of 2010, there were 861 people, 358 households, and 239 families living in the village. The population density was 1,345.3 inhabitants per square mile (519.4/km2). There were 404 housing units at an average density of 631.3 per square mile (243.7/km2). The racial makeup of the village was 99.1% White, 0.1% African American, 0.2% Asian, 0.2% from other races, and 0.3% from two or more races. Hispanic or Latino of any race were 1.5% of the population.
There were 358 households of which 34.4% had children under the age of 18 living with them, 48.6% were married couples living together, 10.9% had a female householder with no husband present, 7.3% had a male householder with no wife present, and 33.2% were non-families. 28.2% of all households were made up of individuals and 11.7% had someone living alone who was 65 years of age or older. The average household size was 2.41 and the average family size was 2.89.